Python Tutorial

Python Flow Control

Python Functions

Python Data Types

Python Date and Time

Python Files

Python String

Python List

Python Dictionary

Python Variable

Python Input/Output

Python Exceptions

Python Advanced

How to Iterate a list as (current, next) pair in Python

To iterate a list as (current, next) pairs in Python, you can use the zip() function along with slicing to create pairs of elements from the original list.

Here's an example:

# The input list
input_list = [1, 2, 3, 4, 5]

# Iterate through the list as (current, next) pairs
for current, next_item in zip(input_list, input_list[1:]):
    print("Current:", current, "Next:", next_item)

In this example, we have an input list called input_list. We use the zip() function to create pairs of elements from the original list by passing two arguments: the original list input_list and a sliced version of the list input_list[1:]. The sliced version starts from the second element of the list. The zip() function returns an iterator of tuples, where each tuple contains a pair of elements from the input lists.

Please note that this approach assumes the next item always exists. If you need to handle cases where there is no next item, you can use a loop with indices and check if the index is within the bounds of the list:

# The input list
input_list = [1, 2, 3, 4, 5]

# Iterate through the list using indices
for index in range(len(input_list)):
    current = input_list[index]
    next_item = input_list[index + 1] if index + 1 < len(input_list) else None
    print("Current:", current, "Next:", next_item)

In this example, we use a loop with indices to iterate through the list. We get the current item by indexing the list with the loop variable index. We get the next item by indexing the list with index + 1 if index + 1 is within the bounds of the list, otherwise, we set the next item to None.

  1. Using zip() to iterate consecutive pairs in a list in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, original_list[1:]))
    print(pairs)
    
  2. Iterate over adjacent elements in a list with enumerate() in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(current, next) for current, next in enumerate(original_list[:-1])]
    print(pairs)
    
  3. Python for loop to iterate over current and next elements in a list:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(original_list[i], original_list[i+1]) for i in range(len(original_list)-1)]
    print(pairs)
    
  4. Create pairs of consecutive elements in a list with list comprehension in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(original_list[i], original_list[i+1]) for i in range(len(original_list)-1)]
    print(pairs)
    
  5. Iterating over adjacent elements in a list using itertools.pairwise() in Python:

    from itertools import pairwise
    
    original_list = [1, 2, 3, 4, 5]
    pairs = list(pairwise(original_list))
    print(pairs)
    
  6. Python zip() with itertools.islice() for (current, next) pair iteration:

    from itertools import islice
    
    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, islice(original_list, 1, None)))
    print(pairs)
    
  7. Iterate over pairs of elements in a list using zip() and slicing in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, original_list[1:]))
    print(pairs)
    
  8. Generate (current, next) pairs with for loop and range() in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(original_list[i], original_list[i+1]) for i in range(len(original_list)-1)]
    print(pairs)
    
  9. Iterate over adjacent elements with zip() and itertools.cycle() in Python:

    from itertools import cycle
    
    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, cycle(original_list[1:])))
    print(pairs)
    
  10. Using zip() and list slicing for (current, next) iteration in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, original_list[1:]))
    print(pairs)
    
  11. Generate consecutive pairs with zip() and itertools.tee() in Python:

    from itertools import tee
    
    original_list = [1, 2, 3, 4, 5]
    current, next_item = tee(original_list)
    next_item = islice(next_item, 1, None)
    pairs = list(zip(current, next_item))
    print(pairs)
    
  12. Iterate over (current, next) pairs with zip() and list comprehension in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(current, next) for current, next in zip(original_list, original_list[1:])]
    print(pairs)
    
  13. Python for loop to iterate over adjacent elements with indexing:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(original_list[i], original_list[i+1]) for i in range(len(original_list)-1)]
    print(pairs)
    
  14. Iterate over consecutive elements in a list with pairwise() function in Python:

    from itertools import pairwise
    
    original_list = [1, 2, 3, 4, 5]
    pairs = list(pairwise(original_list))
    print(pairs)
    
  15. Create (current, next) pairs with zip() and deque in Python:

    from collections import deque
    
    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, deque(original_list, maxlen=len(original_list)-1)))
    print(pairs)
    
  16. Python for loop with enumerate() for (current, next) iteration:

    original_list = [1, 2, 3, 4, 5]
    pairs = [(original_list[i], original_list[i+1]) for i in range(len(original_list)-1)]
    print(pairs)
    
  17. Iterating over adjacent elements with zip() and range() in Python:

    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip(original_list, original_list[1:]))
    print(pairs)
    
  18. Using zip() and zip_longest() for (current, next) iteration in Python:

    from itertools import zip_longest
    
    original_list = [1, 2, 3, 4, 5]
    pairs = list(zip_longest(original_list, original_list[1:]))
    print(pairs)
    
  19. Iterate over consecutive elements with iter() and next() in Python:

    original_list = [1, 2, 3, 4, 5]
    iterator = iter(original_list)
    pairs = [(current, next(iterator)) for current in original_list]
    print(pairs)