MySQL DAYOFYEAR Function: Get The Position Of The Specified Date In The Year

The DAYOFYEAR() function in MySQL is used to return the day of the year for a given date. The returned day of the year is a number from 1 to 366, depending on whether it's a leap year or not.

The syntax for DAYOFYEAR() is:

DAYOFYEAR(date)

Where date is a date or datetime expression from which the day of the year will be returned.

Here's an example of using DAYOFYEAR():

SELECT DAYOFYEAR('2023-05-11');

This will return '131', because May 11, 2023, is the 131st day of the year.

You can also use DAYOFYEAR() with columns in a table. For example, if you have a table named 'events' with a column 'event_date', you can get the day of the year for each event like this:

SELECT event_id, DAYOFYEAR(event_date) AS day_of_year
FROM events;

This would return a result with the event ID and the day of the year for each event.

The DAYOFYEAR() function can be especially useful when you need to perform calculations or comparisons based on the day of the year rather than the date itself.

MySQL DAYOFYEAR Function Example:
- Description: The DAYOFYEAR function returns the day of the year (1 to 366) for a given date.
- Code:
```
-- Example of using DAYOFYEAR
SELECT DAYOFYEAR('2023-01-15') AS day_of_year;
```
Get Position of Date in the Year MySQL:
- Description: Retrieve the position of a date in the year using DAYOFYEAR.
- Code:
```
-- Example getting position of date in the year
SELECT DAYOFYEAR('2023-03-20') AS day_position_in_year;
```

Examples of Using DAYOFYEAR in MySQL Queries:

Description: Utilize DAYOFYEAR in queries to filter or analyze data based on the day of the year.

Code:

-- Example using DAYOFYEAR in WHERE clause
SELECT * FROM events WHERE DAYOFYEAR(event_date) = 100; -- Selecting events on the 100th day of the year